Slip 9 A)
Write a java Program to display following pattern:
1
0 1
0 1 0
1 0 1 0
Answer :
class Slip9A
{
public static void main(String args[]){
int i,j,k=1;;
for(i=1; i<=4; i++){
for(j=1; j<=i; j++){
if(k%2==1){
System.out.print(1 + " ");
}else{
System.out.print(0 + " ");
}
k++;
}
System.out.println();
}
}
}
Output :
Slip 9 B) Write
a java program to validate PAN number and Mobile Number. If it is invalid then
throw user defined Exception “Invalid Data”, otherwise display it.
Answer :
import java.io.*;
class invaliddetails extends Exception{}
class Slip9B{
static int n;
public
static void main( String args[]){
DataInputStream dr = new DataInputStream(System.in);
try {
System.out.print("********* Do you Want to Validate ********* \n1.
Mobile Number Press : 1 \n2. PAN Card Press : 2 \nEnter Number : ");
n = Integer.parseInt(dr.readLine());
switch(n){
case 1 :
System.out.print("Enter
Mobile Number : ");
Long num =
Long.parseLong(dr.readLine());
if(num.toString().matches("(0/91)?[7-9][0-9]{9}")){
System.out.print("Enter Valid Mobile Number..!");
}else{
throw new
invaliddetails();
}
break;
case 2 :
System.out.print("Enter
PAN Number : ");
String str= dr.readLine();
if(str.matches("[A-Z]{5}[0-9]{4}[A-Z]{1}")){
System.out.print("Enter Valid PAN CARD Number..!");
}else{
throw new invaliddetails();
}
break;
default :
throw new invaliddetails();
}
} catch (invaliddetails nz) {
System.out.println("You Enter Invalid Details...!");
}
catch (NumberFormatException e){
System.out.println("You Enter Invalid Details...!");
}
catch(Exception e){}
}
}
Output :
Reviewed by technical_saurabh
on
December 30, 2021
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